Fixed #22715: Corrected sql for defaults of BinaryField on Oracle with Python3

While at it, fixed a problem in returning empty values
(still with BinaryField/Oracle/Python3).

django/db/backends/oracle/base.py

@@ -259,7 +259,10 @@ WHEN (new.%(col_name)s IS NULL)
         # string instead of null, but only if the field accepts the
         # empty string.
         if value is None and field and field.empty_strings_allowed:
-            value = ''
+            if field.get_internal_type() == 'BinaryField':
+                value = bytes()  # same as '' on PY2 but different on PY3
+            else:
+                value = ''
         # Convert 1 or 0 to True or False
         elif value in (1, 0) and field and field.get_internal_type() in ('BooleanField', 'NullBooleanField'):
             value = bool(value)

django/db/backends/oracle/schema.py

@@ -3,6 +3,7 @@ import datetime
 import binascii
 
 from django.utils import six
+from django.utils.text import force_text
 from django.db.backends.schema import BaseDatabaseSchemaEditor
 from django.db.utils import DatabaseError
 
@@ -23,8 +24,9 @@ class DatabaseSchemaEditor(BaseDatabaseSchemaEditor):
             return "'%s'" % value
         elif isinstance(value, six.string_types):
             return "'%s'" % six.text_type(value).replace("\'", "\'\'")
-        elif isinstance(value, buffer):
-            return "'%s'" % binascii.hexlify(value)
+        elif (isinstance(value, six.memoryview) or
+              six.PY3 and isinstance(value, bytes)):
+            return "'%s'" % force_text(binascii.hexlify(value))
         elif isinstance(value, bool):
             return "1" if value else "0"
         else: