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django/docs/howto/writing-migrations.txt
Loic Bistuer bed504d70b Fixed #24351, #24346 -- Changed the signature of allow_migrate().
The new signature enables better support for routing RunPython and
RunSQL operations, especially w.r.t. reusable and third-party apps.

This commit also takes advantage of the deprecation cycle for the old
signature to remove the backward incompatibility introduced in #22583;
RunPython and RunSQL won't call allow_migrate() when when the router
has the old signature.

Thanks Aymeric Augustin and Tim Graham for helping shape up the patch.

Refs 22583.
2015-02-20 21:34:09 +07:00

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===========================
Writing database migrations
===========================
This document explains how to structure and write database migrations for
different scenarios you might encounter. For introductory material on
migrations, see :doc:`the topic guide </topics/migrations>`.
.. _data-migrations-and-multiple-databases:
Data migrations and multiple databases
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
When using multiple databases, you may need to figure out whether or not to
run a migration against a particular database. For example, you may want to
**only** run a migration on a particular database.
In order to do that you can check the database connection's alias inside a
``RunPython`` operation by looking at the ``schema_editor.connection.alias``
attribute::
from django.db import migrations
def forwards(apps, schema_editor):
if not schema_editor.connection.alias == 'default':
return
# Your migration code goes here
class Migration(migrations.Migration):
dependencies = [
# Dependencies to other migrations
]
operations = [
migrations.RunPython(forwards),
]
.. versionadded:: 1.8
You can also provide hints that will be passed to the :meth:`allow_migrate()`
method of database routers as ``**hints``:
.. snippet::
:filename: myapp/dbrouters.py
class MyRouter(object):
def allow_migrate(self, db, app_label, model_name=None, **hints):
if 'target_db' in hints:
return db == hints['target_db']
return True
Then, to leverage this in your migrations, do the following::
from django.db import migrations
def forwards(apps, schema_editor):
# Your migration code goes here
class Migration(migrations.Migration):
dependencies = [
# Dependencies to other migrations
]
operations = [
migrations.RunPython(forwards, hints={'target_db': 'default'}),
]
If your ``RunPython`` or ``RunSQL`` operation only affects one model, it's good
practice to pass ``model_name`` as a hint to make it as transparent as possible
to the router. This is especially important for reusable and third-party apps.
Migrations that add unique fields
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Applying a "plain" migration that adds a unique non-nullable field to a table
with existing rows will raise an error because the value used to populate
existing rows is generated only once, thus breaking the unique constraint.
Therefore, the following steps should be taken. In this example, we'll add a
non-nullable :class:`~django.db.models.UUIDField` with a default value. Modify
the respective field according to your needs.
* Add the field on your model with ``default=...`` and ``unique=True``
arguments. In the example, we use ``uuid.uuid4`` for the default.
* Run the :djadmin:`makemigrations` command.
* Edit the created migration file.
The generated migration class should look similar to this::
class Migration(migrations.Migration):
dependencies = [
('myapp', '0003_auto_20150129_1705'),
]
operations = [
migrations.AddField(
model_name='mymodel',
name='uuid',
field=models.UUIDField(max_length=32, unique=True, default=uuid.uuid4),
),
]
You will need to make three changes:
* Add a second :class:`~django.db.migrations.operations.AddField` operation
copied from the generated one and change it to
:class:`~django.db.migrations.operations.AlterField`.
* On the first operation (``AddField``), change ``unique=True`` to
``null=True`` -- this will create the intermediary null field.
* Between the two operations, add a
:class:`~django.db.migrations.operations.RunPython` or
:class:`~django.db.migrations.operations.RunSQL` operation to generate a
unique value (UUID in the example) for each existing row.
The resulting migration should look similar to this::
# -*- coding: utf-8 -*-
from __future__ import unicode_literals
from django.db import migrations, models
import uuid
def gen_uuid(apps, schema_editor):
MyModel = apps.get_model('myapp', 'MyModel')
for row in MyModel.objects.all():
row.uuid = uuid.uuid4()
row.save()
class Migration(migrations.Migration):
dependencies = [
('myapp', '0003_auto_20150129_1705'),
]
operations = [
migrations.AddField(
model_name='mymodel',
name='uuid',
field=models.UUIDField(default=uuid.uuid4, null=True),
),
# omit reverse_code=... if you don't want the migration to be reversible.
migrations.RunPython(gen_uuid, reverse_code=migrations.RunPython.noop),
migrations.AlterField(
model_name='mymodel',
name='uuid',
field=models.UUIDField(default=uuid.uuid4, unique=True),
),
]
* Now you can apply the migration as usual with the :djadmin:`migrate` command.
Note there is a race condition if you allow objects to be created while this
migration is running. Objects created after the ``AddField`` and before
``RunPython`` will have their original ``uuid``s overwritten.