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145 lines
3.6 KiB
Python
145 lines
3.6 KiB
Python
"""
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Models can have a ``managed`` attribute, which specifies whether the SQL code
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is generated for the table on various manage.py operations.
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"""
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from django.db import models
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from django.utils.encoding import python_2_unicode_compatible
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# All of these models are created in the database by Django.
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@python_2_unicode_compatible
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class A01(models.Model):
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f_a = models.CharField(max_length=10, db_index=True)
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f_b = models.IntegerField()
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class Meta:
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db_table = 'a01'
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def __str__(self):
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return self.f_a
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@python_2_unicode_compatible
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class B01(models.Model):
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fk_a = models.ForeignKey(A01)
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f_a = models.CharField(max_length=10, db_index=True)
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f_b = models.IntegerField()
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class Meta:
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db_table = 'b01'
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# 'managed' is True by default. This tests we can set it explicitly.
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managed = True
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def __str__(self):
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return self.f_a
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@python_2_unicode_compatible
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class C01(models.Model):
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mm_a = models.ManyToManyField(A01, db_table='d01')
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f_a = models.CharField(max_length=10, db_index=True)
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f_b = models.IntegerField()
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class Meta:
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db_table = 'c01'
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def __str__(self):
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return self.f_a
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# All of these models use the same tables as the previous set (they are shadows
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# of possibly a subset of the columns). There should be no creation errors,
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# since we have told Django they aren't managed by Django.
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@python_2_unicode_compatible
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class A02(models.Model):
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f_a = models.CharField(max_length=10, db_index=True)
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class Meta:
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db_table = 'a01'
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managed = False
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def __str__(self):
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return self.f_a
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@python_2_unicode_compatible
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class B02(models.Model):
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class Meta:
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db_table = 'b01'
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managed = False
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fk_a = models.ForeignKey(A02)
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f_a = models.CharField(max_length=10, db_index=True)
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f_b = models.IntegerField()
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def __str__(self):
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return self.f_a
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# To re-use the many-to-many intermediate table, we need to manually set up
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# things up.
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@python_2_unicode_compatible
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class C02(models.Model):
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mm_a = models.ManyToManyField(A02, through="Intermediate")
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f_a = models.CharField(max_length=10, db_index=True)
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f_b = models.IntegerField()
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class Meta:
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db_table = 'c01'
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managed = False
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def __str__(self):
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return self.f_a
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class Intermediate(models.Model):
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a02 = models.ForeignKey(A02, db_column="a01_id")
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c02 = models.ForeignKey(C02, db_column="c01_id")
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class Meta:
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db_table = 'd01'
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managed = False
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# These next models test the creation (or not) of many to many join tables
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# between managed and unmanaged models. A join table between two unmanaged
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# models shouldn't be automatically created (see #10647).
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#
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# Firstly, we need some models that will create the tables, purely so that the
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# tables are created. This is a test setup, not a requirement for unmanaged
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# models.
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class Proxy1(models.Model):
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class Meta:
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db_table = "unmanaged_models_proxy1"
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class Proxy2(models.Model):
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class Meta:
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db_table = "unmanaged_models_proxy2"
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class Unmanaged1(models.Model):
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class Meta:
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managed = False
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db_table = "unmanaged_models_proxy1"
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# Unmanged with an m2m to unmanaged: the intermediary table won't be created.
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class Unmanaged2(models.Model):
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mm = models.ManyToManyField(Unmanaged1)
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class Meta:
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managed = False
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db_table = "unmanaged_models_proxy2"
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# Here's an unmanaged model with an m2m to a managed one; the intermediary
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# table *will* be created (unless given a custom `through` as for C02 above).
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class Managed1(models.Model):
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mm = models.ManyToManyField(Unmanaged1)
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