From 8590d05d44a4f3df56d988229e43d66c37df79da Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?Alexander=20Lazarevi=C4=87?= <laza@e11bits.com>
Date: Wed, 13 Nov 2024 09:01:57 +0100
Subject: [PATCH] Fixed #35887 -- Added imports and admin.site.register to
 non-partial admin inline doc examples.

---
 docs/ref/contrib/admin/index.txt | 23 ++++++++++++++++-------
 docs/topics/db/multi-db.txt      |  4 ++++
 2 files changed, 20 insertions(+), 7 deletions(-)

diff --git a/docs/ref/contrib/admin/index.txt b/docs/ref/contrib/admin/index.txt
index d9e12f0165..1b02b7d403 100644
--- a/docs/ref/contrib/admin/index.txt
+++ b/docs/ref/contrib/admin/index.txt
@@ -2251,6 +2251,7 @@ information.
     inlines to a model by specifying them in a ``ModelAdmin.inlines``::
 
         from django.contrib import admin
+        from myapp.models import Author, Book
 
 
         class BookInline(admin.TabularInline):
@@ -2262,6 +2263,9 @@ information.
                 BookInline,
             ]
 
+
+        admin.site.register(Author, AuthorAdmin)
+
     Django provides two subclasses of ``InlineModelAdmin`` and they are:
 
     * :class:`~django.contrib.admin.TabularInline`
@@ -2494,6 +2498,10 @@ Take this model for instance::
     from django.db import models
 
 
+    class Person(models.Model):
+        name = models.CharField(max_length=128)
+
+
     class Friendship(models.Model):
         to_person = models.ForeignKey(
             Person, on_delete=models.CASCADE, related_name="friends"
@@ -2507,7 +2515,7 @@ you need to explicitly define the foreign key since it is unable to do so
 automatically::
 
     from django.contrib import admin
-    from myapp.models import Friendship
+    from myapp.models import Friendship, Person
 
 
     class FriendshipInline(admin.TabularInline):
@@ -2520,6 +2528,9 @@ automatically::
             FriendshipInline,
         ]
 
+
+    admin.site.register(Person, PersonAdmin)
+
 Working with many-to-many models
 --------------------------------
 
@@ -2548,24 +2559,22 @@ If you want to display many-to-many relations using an inline, you can do
 so by defining an ``InlineModelAdmin`` object for the relationship::
 
     from django.contrib import admin
+    from myapp.models import Group
 
 
     class MembershipInline(admin.TabularInline):
         model = Group.members.through
 
 
-    class PersonAdmin(admin.ModelAdmin):
-        inlines = [
-            MembershipInline,
-        ]
-
-
     class GroupAdmin(admin.ModelAdmin):
         inlines = [
             MembershipInline,
         ]
         exclude = ["members"]
 
+
+    admin.site.register(Group, GroupAdmin)
+
 There are two features worth noting in this example.
 
 Firstly - the ``MembershipInline`` class references ``Group.members.through``.
diff --git a/docs/topics/db/multi-db.txt b/docs/topics/db/multi-db.txt
index be7e9953fa..11be913f4c 100644
--- a/docs/topics/db/multi-db.txt
+++ b/docs/topics/db/multi-db.txt
@@ -683,6 +683,10 @@ Once you've written your model admin definitions, they can be
 registered with any ``Admin`` instance::
 
     from django.contrib import admin
+    from myapp.models import Author, Book, Publisher
+
+    # Import our custom ModelAdmin and TabularInline from where they're defined.
+    from myproject.admin import MultiDBModelAdmin, MultiDBTabularInline
 
 
     # Specialize the multi-db admin objects for use with specific models.