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Fixed #13902 -- Fixed admin list_filter so it doesn't show duplicate results when it includes a field spec that involves m2m relationships with an intermediate model. Thanks Iván Raskovsky for the report and patch.
git-svn-id: http://code.djangoproject.com/svn/django/trunk@15526 bcc190cf-cafb-0310-a4f2-bffc1f526a37
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@@ -1,5 +1,4 @@
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from django.db import models
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from django.contrib import admin
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class Parent(models.Model):
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name = models.CharField(max_length=128)
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@@ -7,3 +6,44 @@ class Parent(models.Model):
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class Child(models.Model):
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parent = models.ForeignKey(Parent, editable=False, null=True)
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name = models.CharField(max_length=30, blank=True)
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class Genre(models.Model):
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name = models.CharField(max_length=20)
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class Band(models.Model):
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name = models.CharField(max_length=20)
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nr_of_members = models.PositiveIntegerField()
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genres = models.ManyToManyField(Genre)
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class Musician(models.Model):
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name = models.CharField(max_length=30)
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def __unicode__(self):
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return self.name
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class Group(models.Model):
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name = models.CharField(max_length=30)
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members = models.ManyToManyField(Musician, through='Membership')
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def __unicode__(self):
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return self.name
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class Membership(models.Model):
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music = models.ForeignKey(Musician)
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group = models.ForeignKey(Group)
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role = models.CharField(max_length=15)
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class Quartet(Group):
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pass
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class ChordsMusician(Musician):
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pass
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class ChordsBand(models.Model):
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name = models.CharField(max_length=30)
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members = models.ManyToManyField(ChordsMusician, through='Invitation')
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class Invitation(models.Model):
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player = models.ForeignKey(ChordsMusician)
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band = models.ForeignKey(ChordsBand)
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instrument = models.CharField(max_length=15)
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