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Fixed #31103 -- Improved pagination topic documentation.
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@ -10,8 +10,8 @@ The ``Paginator`` class
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Under the hood, all methods of pagination use the
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:class:`~django.core.paginator.Paginator` class. It does all the heavy lifting
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of actually splitting a ``QuerySet`` into parts and handing them over to other
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components.
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of actually splitting a ``QuerySet`` into :class:`~django.core.paginator.Page`
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objects.
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Example
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=======
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@ -82,52 +82,25 @@ Paginating a ``ListView``
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=========================
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:class:`django.views.generic.list.ListView` provides a builtin way to paginate
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the displayed list. You can do this by adding
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the displayed list. You can do this by adding a
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:attr:`~django.views.generic.list.MultipleObjectMixin.paginate_by` attribute to
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your view class, for example::
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from django.views.generic import ListView
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from myapp.models import Contacts
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from myapp.models import Contact
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class ContactsList(ListView):
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class ContactList(ListView):
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paginate_by = 2
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model = Contacts
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model = Contact
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The only thing your users will be missing is a way to navigate to the next or
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previous page. To achieve this, add links to the next and previous page, like
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shown in the below example ``list.html``.
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.. _using-paginator-in-view:
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Using ``Paginator`` in a view
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=============================
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Here's a slightly more complex example using
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:class:`~django.core.paginator.Paginator` in a view to paginate a queryset. We
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give both the view and the accompanying template to show how you can display
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the results. This example assumes you have a ``Contacts`` model that has
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already been imported.
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The view function looks like this::
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from django.core.paginator import Paginator
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from django.shortcuts import render
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def listing(request):
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contact_list = Contacts.objects.all()
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paginator = Paginator(contact_list, 25) # Show 25 contacts per page
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page = request.GET.get('page')
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contacts = paginator.get_page(page)
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return render(request, 'list.html', {'contacts': contacts})
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In the template :file:`list.html`, you'll want to include navigation between
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pages along with any interesting information from the objects themselves:
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This limits the number of objects per page and adds a ``paginator`` and
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``page_obj`` to the ``context``. To allow your users to navigate between pages,
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add links to the next and previous page, in your template like this:
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.. code-block:: html+django
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{% for contact in contacts %}
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{% for contact in page_obj %}
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{# Each "contact" is a Contact model object. #}
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{{ contact.full_name|upper }}<br>
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...
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@ -135,18 +108,42 @@ pages along with any interesting information from the objects themselves:
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<div class="pagination">
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<span class="step-links">
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{% if contacts.has_previous %}
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{% if page_obj.has_previous %}
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<a href="?page=1">« first</a>
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<a href="?page={{ contacts.previous_page_number }}">previous</a>
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<a href="?page={{ page_obj.previous_page_number }}">previous</a>
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{% endif %}
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<span class="current">
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Page {{ contacts.number }} of {{ contacts.paginator.num_pages }}.
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Page {{ page_obj.number }} of {{ page_obj.paginator.num_pages }}.
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</span>
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{% if contacts.has_next %}
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<a href="?page={{ contacts.next_page_number }}">next</a>
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<a href="?page={{ contacts.paginator.num_pages }}">last »</a>
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{% if page_obj.has_next %}
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<a href="?page={{ page_obj.next_page_number }}">next</a>
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<a href="?page={{ page_obj.paginator.num_pages }}">last »</a>
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{% endif %}
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</span>
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</div>
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.. _using-paginator-in-view:
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Using ``Paginator`` in a view function
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======================================
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Here's an example using :class:`~django.core.paginator.Paginator` in a view
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function to paginate a queryset::
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from django.core.paginator import Paginator
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from django.shortcuts import render
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from myapp.models import Contact
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def listing(request):
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contact_list = Contact.objects.all()
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paginator = Paginator(contact_list, 25) # Show 25 contacts per page.
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page_number = request.GET.get('page')
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page_obj = paginator.get_page(page_number)
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return render(request, 'list.html', {'page_obj': page_obj})
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In the template :file:`list.html`, you can include navigation between pages in
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the same way as in the template for the ``ListView`` above.
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