1
0
mirror of https://github.com/django/django.git synced 2024-12-26 02:56:25 +00:00
django/docs/ref/contrib/admin/actions.txt

407 lines
15 KiB
Plaintext
Raw Normal View History

=============
Admin actions
=============
.. currentmodule:: django.contrib.admin
The basic workflow of Django's admin is, in a nutshell, "select an object,
then change it." This works well for a majority of use cases. However, if you
need to make the same change to many objects at once, this workflow can be
quite tedious.
In these cases, Django's admin lets you write and register "actions" --
functions that get called with a list of objects selected on the change list
page.
If you look at any change list in the admin, you'll see this feature in
action; Django ships with a "delete selected objects" action available to all
models. For example, here's the user module from Django's built-in
:mod:`django.contrib.auth` app:
.. image:: _images/admin-actions.png
.. warning::
The "delete selected objects" action uses :meth:`QuerySet.delete()
<django.db.models.query.QuerySet.delete>` for efficiency reasons, which
has an important caveat: your model's ``delete()`` method will not be
called.
If you wish to override this behavior, you can override
:meth:`.ModelAdmin.delete_queryset` or write a custom action which does
deletion in your preferred manner -- for example, by calling
``Model.delete()`` for each of the selected items.
For more background on bulk deletion, see the documentation on :ref:`object
deletion <topics-db-queries-delete>`.
Read on to find out how to add your own actions to this list.
Writing actions
===============
The easiest way to explain actions is by example, so let's dive in.
A common use case for admin actions is the bulk updating of a model. Imagine a
news application with an ``Article`` model::
from django.db import models
2019-05-15 12:31:42 +00:00
STATUS_CHOICES = [
('d', 'Draft'),
('p', 'Published'),
('w', 'Withdrawn'),
2019-05-15 12:31:42 +00:00
]
class Article(models.Model):
title = models.CharField(max_length=100)
body = models.TextField()
status = models.CharField(max_length=1, choices=STATUS_CHOICES)
def __str__(self):
return self.title
A common task we might perform with a model like this is to update an
article's status from "draft" to "published". We could easily do this in the
admin one article at a time, but if we wanted to bulk-publish a group of
articles, it'd be tedious. So, let's write an action that lets us change an
article's status to "published."
Writing action functions
------------------------
First, we'll need to write a function that gets called when the action is
triggered from the admin. Action functions are regular functions that take
three arguments:
* The current :class:`ModelAdmin`
* An :class:`~django.http.HttpRequest` representing the current request,
* A :class:`~django.db.models.query.QuerySet` containing the set of
objects selected by the user.
Our publish-these-articles function won't need the :class:`ModelAdmin` or the
request object, but we will use the queryset::
def make_published(modeladmin, request, queryset):
queryset.update(status='p')
.. note::
For the best performance, we're using the queryset's :ref:`update method
<topics-db-queries-update>`. Other types of actions might need to deal
with each object individually; in these cases we'd iterate over the
queryset::
for obj in queryset:
do_something_with(obj)
That's actually all there is to writing an action! However, we'll take one
more optional-but-useful step and give the action a "nice" title in the admin.
By default, this action would appear in the action list as "Make published" --
the function name, with underscores replaced by spaces. That's fine, but we
can provide a better, more human-friendly name by giving the
``make_published`` function a ``short_description`` attribute::
def make_published(modeladmin, request, queryset):
queryset.update(status='p')
make_published.short_description = "Mark selected stories as published"
.. note::
This might look familiar; the admin's ``list_display`` option uses the
same technique to provide human-readable descriptions for callback
functions registered there, too.
Adding actions to the :class:`ModelAdmin`
-----------------------------------------
Next, we'll need to inform our :class:`ModelAdmin` of the action. This works
just like any other configuration option. So, the complete ``admin.py`` with
the action and its registration would look like::
from django.contrib import admin
from myapp.models import Article
def make_published(modeladmin, request, queryset):
queryset.update(status='p')
make_published.short_description = "Mark selected stories as published"
class ArticleAdmin(admin.ModelAdmin):
list_display = ['title', 'status']
ordering = ['title']
actions = [make_published]
admin.site.register(Article, ArticleAdmin)
That code will give us an admin change list that looks something like this:
.. image:: _images/adding-actions-to-the-modeladmin.png
That's really all there is to it! If you're itching to write your own actions,
you now know enough to get started. The rest of this document covers more
advanced techniques.
Handling errors in actions
--------------------------
If there are foreseeable error conditions that may occur while running your
action, you should gracefully inform the user of the problem. This means
handling exceptions and using
:meth:`django.contrib.admin.ModelAdmin.message_user` to display a user friendly
description of the problem in the response.
Advanced action techniques
==========================
There's a couple of extra options and possibilities you can exploit for more
advanced options.
Actions as :class:`ModelAdmin` methods
--------------------------------------
The example above shows the ``make_published`` action defined as a function.
That's perfectly fine, but it's not perfect from a code design point of view:
since the action is tightly coupled to the ``Article`` object, it makes sense
to hook the action to the ``ArticleAdmin`` object itself.
You can do it like this::
class ArticleAdmin(admin.ModelAdmin):
...
actions = ['make_published']
def make_published(self, request, queryset):
queryset.update(status='p')
make_published.short_description = "Mark selected stories as published"
Notice first that we've moved ``make_published`` into a method and renamed the
2013-03-22 09:50:45 +00:00
``modeladmin`` parameter to ``self``, and second that we've now put the string
``'make_published'`` in ``actions`` instead of a direct function reference. This
tells the :class:`ModelAdmin` to look up the action as a method.
Defining actions as methods gives the action more idiomatic access to the
:class:`ModelAdmin` itself, allowing the action to call any of the methods
provided by the admin.
.. _custom-admin-action:
For example, we can use ``self`` to flash a message to the user informing them
that the action was successful::
from django.contrib import messages
from django.utils.translation import ngettext
class ArticleAdmin(admin.ModelAdmin):
...
def make_published(self, request, queryset):
updated = queryset.update(status='p')
self.message_user(request, ngettext(
'%d story was successfully marked as published.',
'%d stories were successfully marked as published.',
updated,
) % updated, messages.SUCCESS)
This make the action match what the admin itself does after successfully
performing an action:
.. image:: _images/actions-as-modeladmin-methods.png
Actions that provide intermediate pages
---------------------------------------
By default, after an action is performed the user is redirected back to the
original change list page. However, some actions, especially more complex ones,
will need to return intermediate pages. For example, the built-in delete action
asks for confirmation before deleting the selected objects.
To provide an intermediary page, return an :class:`~django.http.HttpResponse`
(or subclass) from your action. For example, you might write a export function
that uses Django's :doc:`serialization functions </topics/serialization>` to
dump some selected objects as JSON::
from django.core import serializers
from django.http import HttpResponse
def export_as_json(modeladmin, request, queryset):
response = HttpResponse(content_type="application/json")
serializers.serialize("json", queryset, stream=response)
return response
Generally, something like the above isn't considered a great idea. Most of the
time, the best practice will be to return an
:class:`~django.http.HttpResponseRedirect` and redirect the user to a view
you've written, passing the list of selected objects in the GET query string.
This allows you to provide complex interaction logic on the intermediary
pages. For example, if you wanted to provide a more complete export function,
you'd want to let the user choose a format, and possibly a list of fields to
include in the export. The best thing to do would be to write a small action
that redirects to your custom export view::
from django.contrib.contenttypes.models import ContentType
from django.http import HttpResponseRedirect
def export_selected_objects(modeladmin, request, queryset):
selected = queryset.values_list('pk', flat=True)
ct = ContentType.objects.get_for_model(queryset.model)
return HttpResponseRedirect('/export/?ct=%s&ids=%s' % (
ct.pk,
','.join(str(pk) for pk in selected),
))
As you can see, the action is rather short; all the complex logic would belong
in your export view. This would need to deal with objects of any type, hence
the business with the ``ContentType``.
Writing this view is left as an exercise to the reader.
.. _adminsite-actions:
Making actions available site-wide
----------------------------------
.. method:: AdminSite.add_action(action, name=None)
Some actions are best if they're made available to *any* object in the admin
site -- the export action defined above would be a good candidate. You can
make an action globally available using :meth:`AdminSite.add_action()`. For
example::
from django.contrib import admin
admin.site.add_action(export_selected_objects)
This makes the ``export_selected_objects`` action globally available as an
action named "export_selected_objects". You can explicitly give the action
2013-07-28 01:45:25 +00:00
a name -- good if you later want to programmatically :ref:`remove the action
<disabling-admin-actions>` -- by passing a second argument to
:meth:`AdminSite.add_action()`::
admin.site.add_action(export_selected_objects, 'export_selected')
.. _disabling-admin-actions:
Disabling actions
-----------------
Sometimes you need to disable certain actions -- especially those
:ref:`registered site-wide <adminsite-actions>` -- for particular objects.
There's a few ways you can disable actions:
Disabling a site-wide action
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
.. method:: AdminSite.disable_action(name)
If you need to disable a :ref:`site-wide action <adminsite-actions>` you can
call :meth:`AdminSite.disable_action()`.
For example, you can use this method to remove the built-in "delete selected
objects" action::
admin.site.disable_action('delete_selected')
Once you've done the above, that action will no longer be available
site-wide.
If, however, you need to re-enable a globally-disabled action for one
particular model, list it explicitly in your ``ModelAdmin.actions`` list::
# Globally disable delete selected
admin.site.disable_action('delete_selected')
# This ModelAdmin will not have delete_selected available
class SomeModelAdmin(admin.ModelAdmin):
actions = ['some_other_action']
...
# This one will
class AnotherModelAdmin(admin.ModelAdmin):
actions = ['delete_selected', 'a_third_action']
...
Disabling all actions for a particular :class:`ModelAdmin`
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
If you want *no* bulk actions available for a given :class:`ModelAdmin`, set
:attr:`ModelAdmin.actions` to ``None``::
class MyModelAdmin(admin.ModelAdmin):
actions = None
This tells the :class:`ModelAdmin` to not display or allow any actions,
including any :ref:`site-wide actions <adminsite-actions>`.
Conditionally enabling or disabling actions
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
.. method:: ModelAdmin.get_actions(request)
Finally, you can conditionally enable or disable actions on a per-request
(and hence per-user basis) by overriding :meth:`ModelAdmin.get_actions`.
This returns a dictionary of actions allowed. The keys are action names, and
the values are ``(function, name, short_description)`` tuples.
For example, if you only want users whose names begin with 'J' to be able
to delete objects in bulk::
class MyModelAdmin(admin.ModelAdmin):
...
def get_actions(self, request):
actions = super().get_actions(request)
if request.user.username[0].upper() != 'J':
if 'delete_selected' in actions:
del actions['delete_selected']
return actions
.. _admin-action-permissions:
Setting permissions for actions
-------------------------------
Actions may limit their availability to users with specific permissions by
setting an ``allowed_permissions`` attribute on the action function::
def make_published(modeladmin, request, queryset):
queryset.update(status='p')
make_published.allowed_permissions = ('change',)
The ``make_published()`` action will only be available to users that pass the
:meth:`.ModelAdmin.has_change_permission` check.
If ``allowed_permissions`` has more than one permission, the action will be
available as long as the user passes at least one of the checks.
Available values for ``allowed_permissions`` and the corresponding method
checks are:
- ``'add'``: :meth:`.ModelAdmin.has_add_permission`
- ``'change'``: :meth:`.ModelAdmin.has_change_permission`
- ``'delete'``: :meth:`.ModelAdmin.has_delete_permission`
- ``'view'``: :meth:`.ModelAdmin.has_view_permission`
You can specify any other value as long as you implement a corresponding
``has_<value>_permission(self, request)`` method on the ``ModelAdmin``.
For example::
from django.contrib import admin
from django.contrib.auth import get_permission_codename
class ArticleAdmin(admin.ModelAdmin):
actions = ['make_published']
def make_published(self, request, queryset):
queryset.update(status='p')
make_published.allowed_permissions = ('publish',)
def has_publish_permission(self, request):
"""Does the user have the publish permission?"""
opts = self.opts
codename = get_permission_codename('publish', opts)
return request.user.has_perm('%s.%s' % (opts.app_label, codename))